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Sweepstakes Prize (1): Winner will receive a trip for four (4) (for winner and three [3] guests) to winner's choice of destination city within the fifty (50) United States (up to $10,000 for total cost of trip). Trip includes: round-trip coach class air transportation from a major commercial airport near winner's residence to winner's choice of destination city within the fifty (50) United States for winner and three (3) guests, standard hotel accommodations (two [2] rooms/double occupancy each) (number of nights of hotel stay will depend on the destination city and total cost of the trip; $10,000 limit for cost of entire trip), $5,000 in Amazon.com Gift Cards (for winner only), a Samsung Notebook 9 laptop, a Galaxy tablet (for winner only), and a Samsung device (device determined by Sponsor in its sole discretion). ARV of the Sweepstakes Prize is $18,000.00. If cost of trip is under $10,000, winner will receive a check for the remaining amount. Trip must be taken by September 13, 2019.